49^{4^x}=7

Lösung

4 9^{4^{x}} = 7

x = - \frac{1}{2}

Dezimale

x = - 0.5

Schritte zur Lösung

4 9^{4^{x}} = 7

Wende Exponentenregel an

(1 + 2 x) ln (2) = ln (1)

Löse

(1 + 2 x) ln (2) = ln (1) : x = - \frac{1}{2}

x = - \frac{1}{2}

(5^{3})^{n} = 5^{18}

2^{x} - 2^{- x} = 1

e x - x e^{5 x - 1} = 0

2^{x} \cdot 3^{x^{2}} = 6

e^{\frac{x}{2}} = 0