1/9 =3^{2x+2}

Lösung

\frac{1}{9} = 3^{2 x + 2}

x = - 2

Schritte zur Lösung

\frac{1}{9} = 3^{2 x + 2}

Wende Exponentenregel an

- 2 = 2 x + 2

Löse

- 2 = 2 x + 2 : x = - 2

x = - 2

e^{4 x + 5} = 1

25 (5^{2 x}) - 626 (5^{x}) + 25 = 0

e^{x} = e^{- 2 x}

5 e^{3 t} = 8 e^{2 t}

125 = (\frac{1}{25})^{y - 1}