5^{7x+5}=2

Lösung

5^{7 x + 5} = 2

x = \frac{ln ( 2 ) - 5 ln ( 5 )}{7 ln ( 5 )}

Dezimale

x = - 0.65276 \dots

Schritte zur Lösung

5^{7 x + 5} = 2

Wende Exponentenregel an

(7 x + 5) ln (5) = ln (2)

Löse

(7 x + 5) ln (5) = ln (2) : x = \frac{ln ( 2 ) - 5 ln ( 5 )}{7 ln ( 5 )}

x = \frac{ln ( 2 ) - 5 ln ( 5 )}{7 ln ( 5 )}

8^{2 x} - 1 = 29

so l v e f or z, 1 = e^{2 x + 2 y + z}

1 0^{x} = 100000

4^{x} - 4^{- 2 x} = 3

14 (3 + e^{- x})^{- 1} = 3