7^{5x+4}=21

Lösung

7^{5 x + 4} = 21

x = \frac{ln ( \frac{3}{343} )}{5 ln ( 7 )}

Dezimale

x = - 0.48708 \dots

Schritte zur Lösung

7^{5 x + 4} = 21

Wende Exponentenregel an

(5 x + 4) ln (7) = ln (21)

Löse

(5 x + 4) ln (7) = ln (21) : x = \frac{ln ( \frac{3}{343} )}{5 ln ( 7 )}

x = \frac{ln ( \frac{3}{343} )}{5 ln ( 7 )}

3^{4^{x + 3}} = 3^{1 6^{2 x - 5}}

110624.8 = 55000 \cdot (1.15)^{x}

3^{x - x^{2}} = \frac{1}{9 ^{x}}

7^{x} = 4 9^{2}

e^{x} = - \frac{1}{2}