8^{2x+1}=\sqrt[3]{4^{x-1}}

Lösung

8^{2 x + 1} = 3 4^{x - 1}

x = - \frac{11}{16}

Dezimale

x = - 0.6875

Schritte zur Lösung

8^{2 x + 1} = 3 4^{x - 1}

Wende Exponentenregel an

3 (2 x + 1) = \frac{2}{3} (x - 1)

Löse

3 (2 x + 1) = \frac{2}{3} (x - 1) : x = - \frac{11}{16}

x = - \frac{11}{16}

3^{x - 1} + 3^{x} + 3^{x + 1} = 117

2^{2} n = 4^{n}

e^{k} = 2

e^{x} = e^{- 4 x}

so l v e f or x, e^{e^{x}} = 10