4^{x-3}=32^{2x+1}

Lösung

4^{x - 3} = 3 2^{2 x + 1}

x = - \frac{11}{8}

Dezimale

x = - 1.375

Schritte zur Lösung

4^{x - 3} = 3 2^{2 x + 1}

Wende Exponentenregel an

2 (x - 3) = 5 (2 x + 1)

Löse

2 (x - 3) = 5 (2 x + 1) : x = - \frac{11}{8}

x = - \frac{11}{8}

5^{2 x - 1} = 4^{x + 3}

280 = 1400 - 1400 (0.9)^{t}

e^{- 3 t} = 0

e^{- 2 x} = (e^{5})^{x + 7}

11 = 1 1^{2 x}