25^{2x+4}=125*5^{x-1}

Lösung

2 5^{2 x + 4} = 125 \cdot 5^{x - 1}

x = - 2

Schritte zur Lösung

2 5^{2 x + 4} = 125 \cdot 5^{x - 1}

Wende Exponentenregel an

2 (2 x + 4) = x + 2

Löse

2 (2 x + 4) = x + 2 : x = - 2

x = - 2

7^{x + 1} - 2 = 2 (7^{x}) + 3

3^{2 x} - 6 \cdot 3^{x} + 5 = 0

2^{2 x} - 2^{x + 1} - 8 = 0

(\frac{1}{64})^{- x - 3} = 16

2^{2 x - 5} = 8^{x + 7}