5^{x^2+2x}=1

Lösung

5^{x^{2} + 2 x} = 1

x = 0, x = - 2

Schritte zur Lösung

5^{x^{2} + 2 x} = 1

Wende Exponentenregel an

(x^{2} + 2 x) ln (5) = ln (1)

Löse

(x^{2} + 2 x) ln (5) = ln (1) : x = 0, x = - 2

x = 0, x = - 2

5 \cdot 2 5^{x + 2} = 12 5^{2 x}

7^{5 x^{2} - 42 x} = 1 0^{125 - 42 x}

so l v e f or t, e^{k t} = \frac{1}{7}

3 ∣ 2^{x} - 1 ∣ = 2^{x}

3 x e^{x} + x^{2} e^{x} = 0