2^x*8^{3x-1}=64

Lösung

2^{x} \cdot 8^{3 x - 1} = 64

x = \frac{9}{10}

Dezimale

x = 0.9

Schritte zur Lösung

2^{x} \cdot 8^{3 x - 1} = 64

Wende Exponentenregel an

x + 3 (3 x - 1) = 6

Löse

x + 3 (3 x - 1) = 6 : x = \frac{9}{10}

x = \frac{9}{10}

6^{x + 1} - 18 (6^{x - 1}) = 108

x^{x} = 2^{1 0^{6}}

6^{3 x + 4} = 3 6^{2 x - 3}

so l v e f or x, (x y)^{x} = e

2^{2 - x} = 5^{x + 1}