2^{2x+1}=20

解

2^{2 x + 1} = 20

x = \frac{ln ( 10 )}{2 ln ( 2 )}

十進法表記

x = 1.66096 \dots

解答ステップ

2^{2 x + 1} = 20

指数の規則を適用する

(2 x + 1) ln (2) = ln (20)

解く

(2 x + 1) ln (2) = ln (20) : x = \frac{ln ( 10 )}{2 ln ( 2 )}

x = \frac{ln ( 10 )}{2 ln ( 2 )}