7^{x+4}=10^x

Lösung

7^{x + 4} = 1 0^{x}

x = \frac{4 ln ( 7 )}{ln ( 10 ) - ln ( 7 )}

Dezimale

x = 21.82278 \dots

Schritte zur Lösung

7^{x + 4} = 1 0^{x}

Wende Exponentenregel an

(x + 4) ln (7) = x ln (10)

Löse

(x + 4) ln (7) = x ln (10) : x = \frac{4 ln ( 7 )}{ln ( 10 ) - ln ( 7 )}

x = \frac{4 ln ( 7 )}{ln ( 10 ) - ln ( 7 )}

1.0 7^{n} = 2

e^{(2 x - 1)} = 3

0.4 = 1.0 5^{2 x + 5} - 1

0 = x (2 - x) e^{(- x + 4)}

4 ∣ 5^{x} - 1 ∣ = 5^{x}