4^{2x+1}=0.5^{3x+2}

Lösung

4^{2 x + 1} = 0. 5^{3 x + 2}

x = - \frac{4}{7}

Dezimale

x = - 0.57142 \dots

Schritte zur Lösung

4^{2 x + 1} = 0. 5^{3 x + 2}

4^{2 x + 1} = (\frac{1}{2})^{3 x + 2}

Wende Exponentenregel an

2 (2 x + 1) = - (3 x + 2)

Löse

2 (2 x + 1) = - (3 x + 2) : x = - \frac{4}{7}

x = - \frac{4}{7}

9^{x + 1} = 2 7^{2 x - 5}

so l v e f or x, e^{x y} = 2

3^{x + 4} + 3^{x + 2} + 3^{x} = 273

4^{x} + 2^{x + 1} = 8

64 = 3 2^{x - 3}