2^x*5^{x-1}=0.01

Lösung

2^{x} \cdot 5^{x - 1} = 0.01

x = \frac{ln ( 0.05 )}{ln ( 10 )}

Dezimale

x = - 1.30102 \dots

Schritte zur Lösung

2^{x} \cdot 5^{x - 1} = 0.01

Wende Exponentenregel an

(x - 1 + 1 + lo g_{2} (5) (x - 1)) ln (2) = ln (0.01)

Löse

(x - 1 + 1 + lo g_{2} (5) (x - 1)) ln (2) = ln (0.01) : x = \frac{ln ( 0.05 )}{ln ( 10 )}

x = \frac{ln ( 0.05 )}{ln ( 10 )}

2^{x + 2} + 2^{x - 1} - 2^{x - 3} = 70

so l v e f or n, p = \frac{1}{1 0 ^{n}}

2^{2 x + 18} = 3^{x - 12}

x e^{x} - e^{x} = 0

6 = e^{x}