2^{3x-1}=6

Lösung

2^{3 x - 1} = 6

x = \frac{ln ( 12 )}{3 ln ( 2 )}

Dezimale

x = 1.19498 \dots

Schritte zur Lösung

2^{3 x - 1} = 6

Wende Exponentenregel an

(3 x - 1) ln (2) = ln (6)

Löse

(3 x - 1) ln (2) = ln (6) : x = \frac{ln ( 12 )}{3 ln ( 2 )}

x = \frac{ln ( 12 )}{3 ln ( 2 )}

e^{x} - 4 = 10

9^{x} + 2 (3^{x}) = 3^{x + 2} - 12

1000000 = 2^{n}

3^{3 x} + 3 = 6561

2^{2 x + 1} + 4^{x - 1} = 9