4^{-2x-1}=16

Lösung

4^{- 2 x - 1} = 16

x = - \frac{3}{2}

Dezimale

x = - 1.5

Schritte zur Lösung

4^{- 2 x - 1} = 16

Wende Exponentenregel an

- 2 x - 1 = 2

Löse

- 2 x - 1 = 2 : x = - \frac{3}{2}

x = - \frac{3}{2}

3^{(- x + 1)} = \frac{1}{81}

e^{2 z} + e^{z} + 1 = 0

2^{11 x} = 2^{x - 4}

4^{3 x + 1} = 1 6^{x + 3}

(2^{x}) (4^{x + 1}) = 8