25^{(x+2)}=1

Lösung

2 5^{(x + 2)} = 1

x = - 2

Schritte zur Lösung

2 5^{(x + 2)} = 1

Wende Exponentenregel an

(x + 2) ln (25) = ln (1)

Löse

(x + 2) ln (25) = ln (1) : x = - 2

x = - 2

1 0^{x^{2} - 4} = 1

2 7^{1 - x} = (\frac{1}{9})^{2 - x}

3500 (1 + 0.25)^{- n} = 500

so l v e f or x, y = e^{k x}

4^{2 x - 1} = 1024