3^{(x^2-4x-5)/(3x-1)}=1

Lösung

3^{\frac{x ^{2} - 4 x - 5}{3 x - 1}} = 1

x = - 1, x = 5

Schritte zur Lösung

3^{\frac{x ^{2} - 4 x - 5}{3 x - 1}} = 1

Wende Exponentenregel an

\frac{x ^{2} - 4 x - 5}{3 x - 1} ln (3) = ln (1)

Löse

\frac{x ^{2} - 4 x - 5}{3 x - 1} ln (3) = ln (1) : x = - 1, x = 5

x = - 1, x = 5

256 = (\frac{1}{4})^{3 x + 2}

170 = 180 (1 - e^{- 0.5 t})

1 0^{\frac{x ^{2} - 1}{x + 1}} = 10

e^{2 x} - e^{x} - 132 = 0

83 = 1 1^{x}