7^{3x+2}=21

Lösung

7^{3 x + 2} = 21

x = \frac{ln ( \frac{3}{7} )}{3 ln ( 7 )}

Dezimale

x = - 0.14514 \dots

Schritte zur Lösung

7^{3 x + 2} = 21

Wende Exponentenregel an

(3 x + 2) ln (7) = ln (21)

Löse

(3 x + 2) ln (7) = ln (21) : x = \frac{ln ( \frac{3}{7} )}{3 ln ( 7 )}

x = \frac{ln ( \frac{3}{7} )}{3 ln ( 7 )}

7^{3 x + 2} = 28

7^{3 x + 2} = 35

3^{2 x + 1} + 3^{x + 2} = 12

5^{x + 1} + 5^{1 - x} = 11

- 7 \cdot 3^{0.25 x} = - 10