xln(e^x)+x=12

Lösung

x ln (e^{x}) + x = 12

x = 3, x = - 4

Schritte zur Lösung

x ln (e^{x}) + x = 12

Wende Exponentenregel an

xx + x = 12

Löse

xx + x = 12 : x = 3, x = - 4

x = 3, x = - 4

x^{10} = 2^{x}

8^{5 x - 7} = 9^{2 x - 3}

0.2 = (\frac{4}{5})^{x}

2^{x + 2} - 3 x (2^{x - 1}) = 20

(1 + x) \cdot 4 = 2^{x}