1.12^x=2

Lösung

1.1 2^{x} = 2

x = \frac{ln ( 2 )}{ln ( 1.12 )}

Dezimale

x = 6.11625 \dots

Schritte zur Lösung

1.1 2^{x} = 2

Wende Exponentenregel an

x ln (1.12) = ln (2)

Löse

x ln (1.12) = ln (2) : x = \frac{ln ( 2 )}{ln ( 1.12 )}

x = \frac{ln ( 2 )}{ln ( 1.12 )}

4^{3 x - 5} = \frac{1}{256}

3000 = 3 \cdot 1 0^{x}

so l v e f or x, e^{- I n x} = 0.2

so l v e f or x, c = e^{x} + x y - y^{2}

3 e^{x} = e^{- x}