2(1/8)^{1-2x}=16^{x+6}

Lösung

2 (\frac{1}{8})^{1 - 2 x} = 1 6^{x + 6}

x = 13

Schritte zur Lösung

2 (\frac{1}{8})^{1 - 2 x} = 1 6^{x + 6}

Wende Exponentenregel an

- 3 (1 - 2 x) + 1 = 4 (x + 6)

Löse

- 3 (1 - 2 x) + 1 = 4 (x + 6) : x = 13

x = 13

2 = 2^{x}

8^{x - 4} = 4^{x + 1}

\frac{4 ^{3 x - 1}}{16} = 64

2^{2 x - 1} - 9 (2^{x - 2}) + 1 = 0

3^{5 x - 1} = 2 7^{x + 3}