2^x*8^{5x-1}=64^x

Lösung

2^{x} \cdot 8^{5 x - 1} = 6 4^{x}

x = \frac{3}{10}

Dezimale

x = 0.3

Schritte zur Lösung

2^{x} \cdot 8^{5 x - 1} = 6 4^{x}

Wende Exponentenregel an

x + 3 (5 x - 1) = 6 x

Löse

x + 3 (5 x - 1) = 6 x : x = \frac{3}{10}

x = \frac{3}{10}

4^{2 x - 7} = 16

2^{2 R - 4} - 5^{2 - R} = 0

6 4^{3 x} = 51 2^{2 x + 12}

8^{x + 2} = (\frac{1}{32})^{- 5 x}

\frac{1}{4 ^{x}} = \frac{1}{64}