64^{2^{1-x}}=8^{2^{x+1}}

Lösung

6 4^{2^{1 - x}} = 8^{2^{x + 1}}

x = \frac{1}{2}

Dezimale

x = 0.5

Schritte zur Lösung

6 4^{2^{1 - x}} = 8^{2^{x + 1}}

Wende Exponentenregel an

- x + 2 = x + 1

Löse

- x + 2 = x + 1 : x = \frac{1}{2}

x = \frac{1}{2}

x^{2} e^{x} - x e^{x} - 2 e^{x} = 0

2^{n - 3} = 8^{n}

2 7^{2} = 3^{x}

(2 x^{2} + 4 x - 16) \cdot 3^{x} = 0

5^{3 x} \cdot 2^{x} = 250