993=10^{((1.25-m+5))/5}

Lösung

993 = 1 0^{\frac{( 1.25 - m + 5 )}{5}}

m = - \frac{5 ln ( 993 )}{ln ( 10 )} + 6.25

Dezimale

m = - 8.73474 \dots

Schritte zur Lösung

993 = 1 0^{\frac{( 1.25 - m + 5 )}{5}}

Wende Exponentenregel an

ln (993) = \frac{1.25 - m + 5}{5} ln (10)

Löse

ln (993) = \frac{1.25 - m + 5}{5} ln (10) : m = - \frac{5 ln ( 993 )}{ln ( 10 )} + 6.25

m = - \frac{5 ln ( 993 )}{ln ( 10 )} + 6.25

2 = 1.0 6^{n}

5 e^{x} + 48 e^{- x} = 46

so l v e f or t, 45 x 1.07 1^{t} = 122

1 6^{x - 3} = 2^{x - 6}

n = 1. 2^{n}