2^{x+5}=2^{2x+1}

Lösung

2^{x + 5} = 2^{2 x + 1}

x = 4

Schritte zur Lösung

2^{x + 5} = 2^{2 x + 1}

Wende Exponentenregel an

x + 5 = 2 x + 1

Löse

x + 5 = 2 x + 1 : x = 4

x = 4

5^{x + 1} - 5^{x - 1} = 24

so l v e f or x, 2 = e^{x}

2 (1 0^{6}) = 1 0^{6} e^{12 k}

64000 = \frac{1}{80} e^{x (210)}

(\frac{1}{6})^{2 x} = 216