3^{x+3}=7^x

Lösung

3^{x + 3} = 7^{x}

x = \frac{3 ln ( 3 )}{ln ( 7 ) - ln ( 3 )}

Dezimale

x = 3.88982 \dots

Schritte zur Lösung

3^{x + 3} = 7^{x}

Wende Exponentenregel an

(x + 3) ln (3) = x ln (7)

Löse

(x + 3) ln (3) = x ln (7) : x = \frac{3 ln ( 3 )}{ln ( 7 ) - ln ( 3 )}

x = \frac{3 ln ( 3 )}{ln ( 7 ) - ln ( 3 )}

5^{x} = 2^{2 x + 1}

2 9^{9 x - 4} = 125

so l v e f or t, N = a e^{- 0.21 \cdot t}

21 6^{- 3 x} = 36

5^{6 - x} = 1