2^x=3^{2x+1}

Lösung

2^{x} = 3^{2 x + 1}

x = \frac{ln ( 3 )}{ln ( 2 ) - 2 ln ( 3 )}

Dezimale

x = - 0.73042 \dots

Schritte zur Lösung

2^{x} = 3^{2 x + 1}

Wende Exponentenregel an

x ln (2) = (2 x + 1) ln (3)

Löse

x ln (2) = (2 x + 1) ln (3) : x = \frac{ln ( 3 )}{ln ( 2 ) - 2 ln ( 3 )}

x = \frac{ln ( 3 )}{ln ( 2 ) - 2 ln ( 3 )}

26 = 3 (5)^{0.75 x} - 8

ln (e^{4 x}) = ln (- 1)

65 = 3 3^{x}

3^{3 x - 2} = 21

2^{x} - 3 = \frac{1}{8}