125^{3x-4}=25^{4x+2}

Lösung

12 5^{3 x - 4} = 2 5^{4 x + 2}

x = 16

Schritte zur Lösung

12 5^{3 x - 4} = 2 5^{4 x + 2}

Wende Exponentenregel an

3 (3 x - 4) = 2 (4 x + 2)

Löse

3 (3 x - 4) = 2 (4 x + 2) : x = 16

x = 16

5 \cdot 2^{4 x} = 15

2^{x + 1} = \frac{100}{0.125}

120 = \frac{3000}{1 + 59 e ^{- b (5)}}

e^{x + 4} = 6

9^{x} = \frac{1}{9 ^{2}}