208(1.04)^t=279(1.01)^t

Lösung

208 (1.04)^{t} = 279 (1.01)^{t}

t = \frac{ln ( 279 ) - ln ( 208 )}{ln ( 1.04 ) - ln ( 1.01 )}

Dezimale

t = 10.03313 \dots

Schritte zur Lösung

208 (1.04)^{t} = 279 (1.01)^{t}

Wende Exponentenregel an

ln (208) + t ln (1.04) = ln (279) + t ln (1.01)

Löse

ln (208) + t ln (1.04) = ln (279) + t ln (1.01) : t = \frac{ln ( 279 ) - ln ( 208 )}{ln ( 1.04 ) - ln ( 1.01 )}

t = \frac{ln ( 279 ) - ln ( 208 )}{ln ( 1.04 ) - ln ( 1.01 )}

15 = A (1 - e^{- k^{2}})

36 = 18 (1 6^{0.0125 x})

1280 = 5 (2^{t})

x^{2} e^{- x} = 0

3^{2 x + 5} = (\frac{1}{27})^{x - 4}