5=17^{t-2}

Lösung

5 = 1 7^{t - 2}

t = \frac{ln ( 5 )}{ln ( 17 )} + 2

Dezimale

t = 2.56806 \dots

Schritte zur Lösung

5 = 1 7^{t - 2}

Wende Exponentenregel an

ln (5) = (t - 2) ln (17)

Löse

ln (5) = (t - 2) ln (17) : t = \frac{ln ( 5 )}{ln ( 17 )} + 2

t = \frac{ln ( 5 )}{ln ( 17 )} + 2

2 = 4^{x}

64 = 8^{x - 2}

4^{(x - 3)} = 5

3 2^{x + 1} = 64

e^{x + 1} = \frac{1}{e}