32^{x+1}=64

Lösung

3 2^{x + 1} = 64

x = \frac{1}{5}

Dezimale

x = 0.2

Schritte zur Lösung

3 2^{x + 1} = 64

Wende Exponentenregel an

5 (x + 1) = 6

Löse

5 (x + 1) = 6 : x = \frac{1}{5}

x = \frac{1}{5}

e^{x + 1} = \frac{1}{e}

2^{x} = 4^{5} \cdot 2^{3}

3^{7 x - 2} = 4^{x + 3}

0.6 4^{t} = \frac{1}{10}

68.6 = 41.8 e^{k (2029 - 2005)}