8^{-4x}=13^{x+4}

Lösung

8^{- 4 x} = 1 3^{x + 4}

x = \frac{4 ln ( 13 )}{- 12 ln ( 2 ) - ln ( 13 )}

Dezimale

x = - 0.94276 \dots

Schritte zur Lösung

8^{- 4 x} = 1 3^{x + 4}

Wende Exponentenregel an

- 4 x ln (8) = (x + 4) ln (13)

Löse

- 4 x ln (8) = (x + 4) ln (13) : x = \frac{4 ln ( 13 )}{- 12 ln ( 2 ) - ln ( 13 )}

x = \frac{4 ln ( 13 )}{- 12 ln ( 2 ) - ln ( 13 )}

5^{2 x} - 2 (5^{x}) = 15

9^{x} = e^{x + 9}

8^{x - 1} = 1

80 = 100 - 30 \cdot e^{- 0.04 t}

so l v e f or x, 5^{x} = y^{2}