\sqrt[4]{16^{x+5}}=4^{x+3}

Lösung

4 1 6^{x + 5} = 4^{x + 3}

x = - 1

Schritte zur Lösung

4 1 6^{x + 5} = 4^{x + 3}

Wende Exponentenregel an

\frac{1}{2} (x + 5) = x + 3

Löse

\frac{1}{2} (x + 5) = x + 3 : x = - 1

x = - 1

5^{x} = 3^{2 x + 1}

7^{2 x + 5} = 5 \cdot (3^{3 x})

2^{x} = \frac{4 ^{x - 2}}{8}

6 e^{1 - x} + 1 = 25

1500000 = 3 (2^{x - 1})