What are the solutions to the equation 3x^3-4x^2+11x+10=0 ?

The solutions to the equation 3x^3-4x^2+11x+10=0 are x=-2/3 ,x=1+2i,x=1-2i

Find the zeros of 3x^3-4x^2+11x+10=0

The zeros of 3x^3-4x^2+11x+10=0 are x=-2/3 ,x=1+2i,x=1-2i

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3 x^{3} - 4 x^{2} + 11 x + 10 = 0

x = - \frac{2}{3}, x = 1 + 2 i, x = 1 - 2 i

Solution steps

3 x^{3} - 4 x^{2} + 11 x + 10 = 0

Factor

3 x^{3} - 4 x^{2} + 11 x + 10 : (3 x + 2) (x^{2} - 2 x + 5)

(3 x + 2) (x^{2} - 2 x + 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 x + 2 = 0 or x^{2} - 2 x + 5 = 0

Solve

3 x + 2 = 0 : x = - \frac{2}{3}

Solve

x^{2} - 2 x + 5 = 0 : x = 1 + 2 i, x = 1 - 2 i

The solutions are

x = - \frac{2}{3}, x = 1 + 2 i, x = 1 - 2 i

6 x^{3} + 2 x^{2} + x - 4 = 0

x^{3} + 6 x^{2} + 5 x = 0

x^{5} - 5 x^{4} + 1 = 0

x^{2} (x - 2) = 0

x^{3} + 9 x^{2} - 81 x - 729 = 0

What are the solutions to the equation 3x^3-4x^2+11x+10=0 ?
The solutions to the equation 3x^3-4x^2+11x+10=0 are x=-2/3 ,x=1+2i,x=1-2i
Find the zeros of 3x^3-4x^2+11x+10=0
The zeros of 3x^3-4x^2+11x+10=0 are x=-2/3 ,x=1+2i,x=1-2i