解答
z8−16i=0
解答
z=22+2+2+i22−2+2,z=22−2−2+i22+2−2,z=−22−2+2+i22+2+2,z=−22+2−2+i22−2−2,z=−22+2+2−i22−2+2,z=−22−2−2−i22+2−2,z=22−2+2−i22+2+2,z=22+2−2−i22−2−2
求解步骤
z8−16i=0
将 16i到右边
z8=16i
For zn=athe solutions are zk=n∣a∣(cos(narg(a)+2kπ)+isin(narg(a)+2kπ)),
k=0,1,…,n−1
对于 n=8,a=16i∣a∣=16
arg(a)=2π
z=816(cos(82π+2⋅0π)+isin(82π+2⋅0π)),z=816(cos(82π+2⋅1π)+isin(82π+2⋅1π)),z=816(cos(82π+2⋅2π)+isin(82π+2⋅2π)),z=816(cos(82π+2⋅3π)+isin(82π+2⋅3π)),z=816(cos(82π+2⋅4π)+isin(82π+2⋅4π)),z=816(cos(82π+2⋅5π)+isin(82π+2⋅5π)),z=816(cos(82π+2⋅6π)+isin(82π+2⋅6π)),z=816(cos(82π+2⋅7π)+isin(82π+2⋅7π))
化简 816(cos(82π+2⋅0π)+isin(82π+2⋅0π)):22+2+2+i22−2+2
化简 816(cos(82π+2⋅1π)+isin(82π+2⋅1π)):22−2−2+i22+2−2
化简 816(cos(82π+2⋅2π)+isin(82π+2⋅2π)):−22−2+2+i22+2+2
化简 816(cos(82π+2⋅3π)+isin(82π+2⋅3π)):−22+2−2+i22−2−2
化简 816(cos(82π+2⋅4π)+isin(82π+2⋅4π)):−22+2+2−i22−2+2
化简 816(cos(82π+2⋅5π)+isin(82π+2⋅5π)):−22−2−2−i22+2−2
化简 816(cos(82π+2⋅6π)+isin(82π+2⋅6π)):22−2+2−i22+2+2
化简 816(cos(82π+2⋅7π)+isin(82π+2⋅7π)):22+2−2−i22−2−2
z=22+2+2+i22−2+2,z=22−2−2+i22+2−2,z=−22−2+2+i22+2+2,z=−22+2−2+i22−2−2,z=−22+2+2−i22−2+2,z=−22−2−2−i22+2−2,z=22−2+2−i22+2+2,z=22+2−2−i22−2−2