What are the solutions to the equation x^3-8x^2+16x=0 ?

The solutions to the equation x^3-8x^2+16x=0 are x=0,x=4

Find the zeros of x^3-8x^2+16x=0

The zeros of x^3-8x^2+16x=0 are x=0,x=4

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x^{3} - 8 x^{2} + 16 x = 0

x = 0, x = 4

Solution steps

x^{3} - 8 x^{2} + 16 x = 0

Factor

x^{3} - 8 x^{2} + 16 x : x (x - 4)^{2}

x (x - 4)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x - 4 = 0

Solve

x - 4 = 0 : x = 4

The solutions are

x = 0, x = 4

22 - w^{3} = - 7

- x^{3} + 3 x^{2} + x - 3 = 0

m^{4} + m^{3} + m^{2} = 0

x^{3} - 3 x^{2} - 2 x + 6 = 0

(x^{2} - x)^{2} - 14 (x^{2} - x) + 24 = 0

What are the solutions to the equation x^3-8x^2+16x=0 ?
The solutions to the equation x^3-8x^2+16x=0 are x=0,x=4
Find the zeros of x^3-8x^2+16x=0
The zeros of x^3-8x^2+16x=0 are x=0,x=4