ja

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

人気のある代数 >

solvefor y,x=y^6

解

解く

y, x = y^{6}

解

y = 3 x, y = - 3 x, y = \frac{- 3 x + 2 x ^{\frac{2}{3}}}{2} + \frac{3 3 x}{2 - 3 x + 2 x ^{\frac{2}{3}}} i, y = - \frac{- 3 x + 2 x ^{\frac{2}{3}}}{2} - \frac{3 3 x}{2 - 3 x + 2 x ^{\frac{2}{3}}} i, y = - \frac{3 x + 2 x ^{\frac{2}{3}}}{4} + \frac{3 3 x}{4 - \frac{3 x + 2 x ^{\frac{2}{3}}}{4}} i, y = - - \frac{3 x + 2 x ^{\frac{2}{3}}}{4} - \frac{3 3 x}{4 - \frac{3 x + 2 x ^{\frac{2}{3}}}{4}} i, y = \frac{- 3 x + 2 x ^{\frac{2}{3}}}{2} - \frac{3 3 x}{2 - 3 x + 2 x ^{\frac{2}{3}}} i, y = - \frac{- 3 x + 2 x ^{\frac{2}{3}}}{2} + \frac{3 3 x}{2 - 3 x + 2 x ^{\frac{2}{3}}} i, y = - \frac{3 x + 2 x ^{\frac{2}{3}}}{4} - \frac{3 3 x}{4 - \frac{3 x + 2 x ^{\frac{2}{3}}}{4}} i, y = - - \frac{3 x + 2 x ^{\frac{2}{3}}}{4} + \frac{3 3 x}{4 - \frac{3 x + 2 x ^{\frac{2}{3}}}{4}} i

解答ステップ

x = y^{6}

辺を交換する

y^{6} = x

equationを

u = y^{2}

と以下で書き換える:

u^{3} = y^{6}

u^{3} = x

解く

u^{3} = x : u = 3 x, u = 3 x \frac{- 1 + 3 i}{2}, u = 3 x \frac{- 1 - 3 i}{2}

u = 3 x, u = 3 x \frac{- 1 + 3 i}{2}, u = 3 x \frac{- 1 - 3 i}{2}

再び

u = y^{2}

に置き換えて以下を解く:

y

解く

y^{2} = 3 x : y = 3 x, y = - 3 x

解く

y^{2} = 3 x \frac{- 1 + 3 i}{2} : y = \frac{- 3 x + 2 x ^{\frac{2}{3}}}{2} + \frac{3 3 x}{2 - 3 x + 2 x ^{\frac{2}{3}}} i, y = - \frac{- 3 x + 2 x ^{\frac{2}{3}}}{2} - \frac{3 3 x}{2 - 3 x + 2 x ^{\frac{2}{3}}} i, y = - \frac{3 x + 2 x ^{\frac{2}{3}}}{4} + \frac{3 3 x}{4 - \frac{3 x + 2 x ^{\frac{2}{3}}}{4}} i, y = - - \frac{3 x + 2 x ^{\frac{2}{3}}}{4} - \frac{3 3 x}{4 - \frac{3 x + 2 x ^{\frac{2}{3}}}{4}} i

解く

y^{2} = 3 x \frac{- 1 - 3 i}{2} : y = \frac{- 3 x + 2 x ^{\frac{2}{3}}}{2} - \frac{3 3 x}{2 - 3 x + 2 x ^{\frac{2}{3}}} i, y = - \frac{- 3 x + 2 x ^{\frac{2}{3}}}{2} + \frac{3 3 x}{2 - 3 x + 2 x ^{\frac{2}{3}}} i, y = - \frac{3 x + 2 x ^{\frac{2}{3}}}{4} - \frac{3 3 x}{4 - \frac{3 x + 2 x ^{\frac{2}{3}}}{4}} i, y = - - \frac{3 x + 2 x ^{\frac{2}{3}}}{4} + \frac{3 3 x}{4 - \frac{3 x + 2 x ^{\frac{2}{3}}}{4}} i

解答は

y = 3 x, y = - 3 x, y = \frac{- 3 x + 2 x ^{\frac{2}{3}}}{2} + \frac{3 3 x}{2 - 3 x + 2 x ^{\frac{2}{3}}} i, y = - \frac{- 3 x + 2 x ^{\frac{2}{3}}}{2} - \frac{3 3 x}{2 - 3 x + 2 x ^{\frac{2}{3}}} i, y = - \frac{3 x + 2 x ^{\frac{2}{3}}}{4} + \frac{3 3 x}{4 - \frac{3 x + 2 x ^{\frac{2}{3}}}{4}} i, y = - - \frac{3 x + 2 x ^{\frac{2}{3}}}{4} - \frac{3 3 x}{4 - \frac{3 x + 2 x ^{\frac{2}{3}}}{4}} i, y = \frac{- 3 x + 2 x ^{\frac{2}{3}}}{2} - \frac{3 3 x}{2 - 3 x + 2 x ^{\frac{2}{3}}} i, y = - \frac{- 3 x + 2 x ^{\frac{2}{3}}}{2} + \frac{3 3 x}{2 - 3 x + 2 x ^{\frac{2}{3}}} i, y = - \frac{3 x + 2 x ^{\frac{2}{3}}}{4} - \frac{3 3 x}{4 - \frac{3 x + 2 x ^{\frac{2}{3}}}{4}} i, y = - - \frac{3 x + 2 x ^{\frac{2}{3}}}{4} + \frac{3 3 x}{4 - \frac{3 x + 2 x ^{\frac{2}{3}}}{4}} i

グラフ

人気の例

solvefor y,x=y^7

so l v e f or y, x = y^{7}

z^{4} + 81 = 0

3x^3-7x^2+3x-7=0

3 x^{3} - 7 x^{2} + 3 x - 7 = 0

457551.55=200000(1+x)^5

457551.55 = 200000 (1 + x)^{5}

(x+3)(x^2-2)=x+3

(x + 3) (x^{2} - 2) = x + 3