What are the solutions to the equation (x-1)(x-2)(x-3)=0 ?

The solutions to the equation (x-1)(x-2)(x-3)=0 are x=1,x=2,x=3

Find the zeros of (x-1)(x-2)(x-3)=0

The zeros of (x-1)(x-2)(x-3)=0 are x=1,x=2,x=3

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(x - 1) (x - 2) (x - 3) = 0

x = 1, x = 2, x = 3

Solution steps

(x - 1) (x - 2) (x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or x - 2 = 0 or x - 3 = 0

Solve

x - 1 = 0 : x = 1

Solve

x - 2 = 0 : x = 2

Solve

x - 3 = 0 : x = 3

The solutions are

x = 1, x = 2, x = 3

w^{3} = - 125

(x^{2} - 49) (x^{2} + 16) = 0

x^{3} - 4 x^{2} - 12 x = 0

x^{3} - 9 x + 3 = 0

x^{3} - 2 x^{2} - 2 x + 2 = 0

What are the solutions to the equation (x-1)(x-2)(x-3)=0 ?
The solutions to the equation (x-1)(x-2)(x-3)=0 are x=1,x=2,x=3
Find the zeros of (x-1)(x-2)(x-3)=0
The zeros of (x-1)(x-2)(x-3)=0 are x=1,x=2,x=3