de

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Beliebt Algebra >

12x^3-4x^2-3x+1=0

Lösung

12 x^{3} - 4 x^{2} - 3 x + 1 = 0

Lösung

x = \frac{1}{3}, x = - \frac{1}{2}, x = \frac{1}{2}

+1

Dezimale

x = 0.33333 \dots, x = - 0.5, x = 0.5

Schritte zur Lösung

12 x^{3} - 4 x^{2} - 3 x + 1 = 0

Faktorisiere

12 x^{3} - 4 x^{2} - 3 x + 1 : (3 x - 1) (2 x + 1) (2 x - 1)

(3 x - 1) (2 x + 1) (2 x - 1) = 0

Anwendung des Nullfaktorprinzips: Wenn

ab = 0

dann

a = 0

oder

b = 0

3 x - 1 = 0 or 2 x + 1 = 0 or 2 x - 1 = 0

Löse

3 x - 1 = 0 : x = \frac{1}{3}

Löse

2 x + 1 = 0 : x = - \frac{1}{2}

Löse

2 x - 1 = 0 : x = \frac{1}{2}

Die Lösungen sind

x = \frac{1}{3}, x = - \frac{1}{2}, x = \frac{1}{2}

Graph

Beliebte Beispiele

8 x - 4 = 2 x^{3} - x^{2}

12x^3+20x^2-27x-45=0

12 x^{3} + 20 x^{2} - 27 x - 45 = 0

2 x (x^{2} + 2 x - 6) = 0

x^3+6x^2+x-34=0

x^{3} + 6 x^{2} + x - 34 = 0

6 = - w^{8}