ko

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

인기 있는 대수학 >

6=-w^8

해법

6 = - w^{8}

해법

w = \frac{4 \frac{3}{2}}{2 \cdot 2 ^{\frac{3}{4}} 4 3 - 4 24} + \frac{2 \cdot 2 ^{\frac{3}{4}} 4 3 - 4 24}{2} i, w = - \frac{4 \frac{3}{2}}{2 \cdot 2 ^{\frac{3}{4}} 4 3 - 4 24} - \frac{2 \cdot 2 ^{\frac{3}{4}} 4 3 - 4 24}{2} i, w = - \frac{4 \frac{3}{2}}{4 24 + 2 \cdot 2 ^{\frac{3}{4}} 4 3} + \frac{4 24 + 2 \cdot 2 ^{\frac{3}{4}} 4 3}{2} i, w = \frac{4 \frac{3}{2}}{4 24 + 2 \cdot 2 ^{\frac{3}{4}} 4 3} - \frac{4 24 + 2 \cdot 2 ^{\frac{3}{4}} 4 3}{2} i, w = \frac{4 \frac{3}{2}}{4 24 + 2 \cdot 2 ^{\frac{3}{4}} 4 3} + \frac{4 24 + 2 \cdot 2 ^{\frac{3}{4}} 4 3}{2} i, w = - \frac{4 \frac{3}{2}}{4 24 + 2 \cdot 2 ^{\frac{3}{4}} 4 3} - \frac{4 24 + 2 \cdot 2 ^{\frac{3}{4}} 4 3}{2} i, w = - \frac{4 \frac{3}{2}}{2 \cdot 2 ^{\frac{3}{4}} 4 3 - 4 24} + \frac{2 \cdot 2 ^{\frac{3}{4}} 4 3 - 4 24}{2} i, w = \frac{4 \frac{3}{2}}{2 \cdot 2 ^{\frac{3}{4}} 4 3 - 4 24} - \frac{2 \cdot 2 ^{\frac{3}{4}} 4 3 - 4 24}{2} i

솔루션 단계

6 = - w^{8}

측면 전환

- w^{8} = 6

양쪽을 다음으로 나눕니다

- 1

w^{8} = - 6

다음으로 방정식 다시 쓰기

u = w^{2}

그리고

u^{4} = w^{8}

u^{4} = - 6

u^{4} = - 6

해결 :

u = 4 \frac{3}{2} + 4 \frac{3}{2} i, u = - 4 \frac{3}{2} - 4 \frac{3}{2} i, u = - 4 \frac{3}{2} + 4 \frac{3}{2} i, u = 4 \frac{3}{2} - 4 \frac{3}{2} i

u = 4 \frac{3}{2} + 4 \frac{3}{2} i, u = - 4 \frac{3}{2} - 4 \frac{3}{2} i, u = - 4 \frac{3}{2} + 4 \frac{3}{2} i, u = 4 \frac{3}{2} - 4 \frac{3}{2} i

다시 대체

u = w^{2},

을 해결하다

w

w^{2} = 4 \frac{3}{2} + 4 \frac{3}{2} i

해결 :

w = \frac{4 \frac{3}{2}}{2 \cdot 2 ^{\frac{3}{4}} 4 3 - 4 24} + \frac{2 \cdot 2 ^{\frac{3}{4}} 4 3 - 4 24}{2} i, w = - \frac{4 \frac{3}{2}}{2 \cdot 2 ^{\frac{3}{4}} 4 3 - 4 24} - \frac{2 \cdot 2 ^{\frac{3}{4}} 4 3 - 4 24}{2} i

w^{2} = - 4 \frac{3}{2} - 4 \frac{3}{2} i

해결 :

w = - \frac{4 \frac{3}{2}}{4 24 + 2 \cdot 2 ^{\frac{3}{4}} 4 3} + \frac{4 24 + 2 \cdot 2 ^{\frac{3}{4}} 4 3}{2} i, w = \frac{4 \frac{3}{2}}{4 24 + 2 \cdot 2 ^{\frac{3}{4}} 4 3} - \frac{4 24 + 2 \cdot 2 ^{\frac{3}{4}} 4 3}{2} i

w^{2} = - 4 \frac{3}{2} + 4 \frac{3}{2} i

해결 :

w = \frac{4 \frac{3}{2}}{4 24 + 2 \cdot 2 ^{\frac{3}{4}} 4 3} + \frac{4 24 + 2 \cdot 2 ^{\frac{3}{4}} 4 3}{2} i, w = - \frac{4 \frac{3}{2}}{4 24 + 2 \cdot 2 ^{\frac{3}{4}} 4 3} - \frac{4 24 + 2 \cdot 2 ^{\frac{3}{4}} 4 3}{2} i

w^{2} = 4 \frac{3}{2} - 4 \frac{3}{2} i

해결 :

w = - \frac{4 \frac{3}{2}}{2 \cdot 2 ^{\frac{3}{4}} 4 3 - 4 24} + \frac{2 \cdot 2 ^{\frac{3}{4}} 4 3 - 4 24}{2} i, w = \frac{4 \frac{3}{2}}{2 \cdot 2 ^{\frac{3}{4}} 4 3 - 4 24} - \frac{2 \cdot 2 ^{\frac{3}{4}} 4 3 - 4 24}{2} i

해결책은

w = \frac{4 \frac{3}{2}}{2 \cdot 2 ^{\frac{3}{4}} 4 3 - 4 24} + \frac{2 \cdot 2 ^{\frac{3}{4}} 4 3 - 4 24}{2} i, w = - \frac{4 \frac{3}{2}}{2 \cdot 2 ^{\frac{3}{4}} 4 3 - 4 24} - \frac{2 \cdot 2 ^{\frac{3}{4}} 4 3 - 4 24}{2} i, w = - \frac{4 \frac{3}{2}}{4 24 + 2 \cdot 2 ^{\frac{3}{4}} 4 3} + \frac{4 24 + 2 \cdot 2 ^{\frac{3}{4}} 4 3}{2} i, w = \frac{4 \frac{3}{2}}{4 24 + 2 \cdot 2 ^{\frac{3}{4}} 4 3} - \frac{4 24 + 2 \cdot 2 ^{\frac{3}{4}} 4 3}{2} i, w = \frac{4 \frac{3}{2}}{4 24 + 2 \cdot 2 ^{\frac{3}{4}} 4 3} + \frac{4 24 + 2 \cdot 2 ^{\frac{3}{4}} 4 3}{2} i, w = - \frac{4 \frac{3}{2}}{4 24 + 2 \cdot 2 ^{\frac{3}{4}} 4 3} - \frac{4 24 + 2 \cdot 2 ^{\frac{3}{4}} 4 3}{2} i, w = - \frac{4 \frac{3}{2}}{2 \cdot 2 ^{\frac{3}{4}} 4 3 - 4 24} + \frac{2 \cdot 2 ^{\frac{3}{4}} 4 3 - 4 24}{2} i, w = \frac{4 \frac{3}{2}}{2 \cdot 2 ^{\frac{3}{4}} 4 3 - 4 24} - \frac{2 \cdot 2 ^{\frac{3}{4}} 4 3 - 4 24}{2} i

그래프

인기 있는 예

x^3-4x^2-5x+20=0

x^{3} - 4 x^{2} - 5 x + 20 = 0

x^{4} - 21 x^{2} + 80 = 0

x^{3} + 5 x^{2} = - 6 x

solvefor x,x^3-2x^2-5x+6=0

so l v e f or x, x^{3} - 2 x^{2} - 5 x + 6 = 0

solvefor F,t=(F^3+G)a

so l v e f or F, t = (F^{3} + G) a