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Beliebt Algebra >

4x^3-18x^2+27=0

Lösung

4 x^{3} - 18 x^{2} + 27 = 0

Lösung

x = \frac{3}{2}, x = \frac{3 ( 1 + 3 )}{2}, x = \frac{3 ( 1 - 3 )}{2}

+1

Dezimale

x = 1.5, x = 4.09807 \dots, x = - 1.09807 \dots

Schritte zur Lösung

4 x^{3} - 18 x^{2} + 27 = 0

Faktorisiere

4 x^{3} - 18 x^{2} + 27 : (2 x - 3) (2 x^{2} - 6 x - 9)

(2 x - 3) (2 x^{2} - 6 x - 9) = 0

Anwendung des Nullfaktorprinzips: Wenn

ab = 0

dann

a = 0

oder

b = 0

2 x - 3 = 0 or 2 x^{2} - 6 x - 9 = 0

Löse

2 x - 3 = 0 : x = \frac{3}{2}

Löse

2 x^{2} - 6 x - 9 = 0 : x = \frac{3 ( 1 + 3 )}{2}, x = \frac{3 ( 1 - 3 )}{2}

Die Lösungen sind

x = \frac{3}{2}, x = \frac{3 ( 1 + 3 )}{2}, x = \frac{3 ( 1 - 3 )}{2}

Graph

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0.126825=(1+x)^4-1

0.126825 = (1 + x)^{4} - 1

solvefor x,-5x^3-3y^2=17

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- 6 + x^{4} = - 5

y - y^{3} = 0

x^4-x^3-10x^2-x+1=0

x^{4} - x^{3} - 10 x^{2} - x + 1 = 0