What are the solutions to the equation (3x)^3(2x)^2=2300 ?

The solutions to the equation (3x)^3(2x)^2=2300 are x=\sqrt[5]{575/27}

Find the zeros of (3x)^3(2x)^2=2300

The zeros of (3x)^3(2x)^2=2300 are x=\sqrt[5]{575/27}

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(3 x)^{3} (2 x)^{2} = 2300

Decimal Notation

x = 1.84357 \dots

Solution steps

(3 x)^{3} (2 x)^{2} = 2300

Simplify

108 x^{5} = 2300

Divide both sides by

108

\frac{108 x ^{5}}{108} = \frac{2300}{108}

x^{5} = \frac{575}{27}

For

x^{n} = f (a)

, n is odd, the solution is

y, y^{5} - 1 = x

x^{4} + 6 x^{2} - 3 = 0

- x^{3} + 5 x^{2} + 25 x - 125 = 0

z^{3} = - 1 - i

x^{2} (x + 3) = 0

What are the solutions to the equation (3x)^3(2x)^2=2300 ?
The solutions to the equation (3x)^3(2x)^2=2300 are x=\sqrt[5]{575/27}
Find the zeros of (3x)^3(2x)^2=2300
The zeros of (3x)^3(2x)^2=2300 are x=\sqrt[5]{575/27}