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人気のある代数 >

(2x^2-7x)^2+2x^2-7x=20

解

(2 x^{2} - 7 x)^{2} + 2 x^{2} - 7 x = 20

解

x = 1, x = 4, x = - \frac{1}{2}, x = \frac{5}{2}

+1

十進法表記

x = 1, x = 4, x = - 0.5, x = 2.5

解答ステップ

(2 x^{2} - 7 x)^{2} + 2 x^{2} - 7 x = 20

拡張

(2 x^{2} - 7 x)^{2} + 2 x^{2} - 7 x : 4 x^{4} - 28 x^{3} + 51 x^{2} - 7 x

4 x^{4} - 28 x^{3} + 51 x^{2} - 7 x = 20

20

を左側に移動します

4 x^{4} - 28 x^{3} + 51 x^{2} - 7 x - 20 = 0

因数

4 x^{4} - 28 x^{3} + 51 x^{2} - 7 x - 20 : (x - 1) (x - 4) (2 x + 1) (2 x - 5)

(x - 1) (x - 4) (2 x + 1) (2 x - 5) = 0

零因子の原則を使用:

ab = 0

ならば

a = 0

または

b = 0

x - 1 = 0 or x - 4 = 0 or 2 x + 1 = 0 or 2 x - 5 = 0

解く

x - 1 = 0 : x = 1

解く

x - 4 = 0 : x = 4

解く

2 x + 1 = 0 : x = - \frac{1}{2}

解く

2 x - 5 = 0 : x = \frac{5}{2}

解答は

x = 1, x = 4, x = - \frac{1}{2}, x = \frac{5}{2}

グラフ

人気の例

(x)^3+(3x)^2-x-3=0

(x)^{3} + (3 x)^{2} - x - 3 = 0

(x^2+x+1)^2=x^4+8x^2+1

(x^{2} + x + 1)^{2} = x^{4} + 8 x^{2} + 1

x^{3} + x^{3} = 2

(x - 1)^{3} = 1

6 x^{3} + 13 x^{2} - 4 = 0