What are the solutions to the equation 25x^4-61x^2+36=0 ?

The solutions to the equation 25x^4-61x^2+36=0 are x= 6/5 ,x=-6/5 ,x=1,x=-1

Find the zeros of 25x^4-61x^2+36=0

The zeros of 25x^4-61x^2+36=0 are x= 6/5 ,x=-6/5 ,x=1,x=-1

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25 x^{4} - 61 x^{2} + 36 = 0

x = \frac{6}{5}, x = - \frac{6}{5}, x = 1, x = - 1

Decimal Notation

x = 1.2, x = - 1.2, x = 1, x = - 1

Solution steps

25 x^{4} - 61 x^{2} + 36 = 0

Rewrite the equation with

u = x^{2}

and

u^{2} = x^{4}

25 u^{2} - 61 u + 36 = 0

Solve

25 u^{2} - 61 u + 36 = 0 : u = \frac{36}{25}, u = 1

u = \frac{36}{25}, u = 1

Substitute back

u = x^{2},

solve for

x

Solve

x^{2} = \frac{36}{25} : x = \frac{6}{5}, x = - \frac{6}{5}

Solve

x^{2} = 1 : x = 1, x = - 1

The solutions are

x = \frac{6}{5}, x = - \frac{6}{5}, x = 1, x = - 1

y = x^{3}, x

x^{3} = 49

x^{3} = 48

x^{3} = 50

2640.57 = 7.37 E - 9 x^{4} + 7 x

What are the solutions to the equation 25x^4-61x^2+36=0 ?
The solutions to the equation 25x^4-61x^2+36=0 are x= 6/5 ,x=-6/5 ,x=1,x=-1
Find the zeros of 25x^4-61x^2+36=0
The zeros of 25x^4-61x^2+36=0 are x= 6/5 ,x=-6/5 ,x=1,x=-1