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人気のある代数 >

ax^2bx+c=0

解

a x^{2} b x + c = 0

解

x = - 3 \frac{c}{ab}, x = - \frac{3 c ( - 1 + 3 i )}{2 3 ab}, x = - \frac{3 c ( - 1 - 3 i )}{2 3 ab}; a \neq = 0

解答ステップ

a x^{2} b x + c = 0

c

を右側に移動します

a x^{2} b x = - c

簡素化

ab x^{3} = - c

以下で両辺を割る

ab; a \neq = 0

\frac{ab x ^{3}}{ab} = \frac{- c}{ab}; a \neq = 0

x^{3} = - \frac{c}{ab}; a \neq = 0

x^{3} = f (a)

では, 解は

x = 3 f (a), 3 f (a) \frac{- 1 - 3 i}{2}, 3 f (a) \frac{- 1 + 3 i}{2}

x = 3 - \frac{c}{ab}, x = 3 - \frac{c}{ab} \frac{- 1 + 3 i}{2}, x = 3 - \frac{c}{ab} \frac{- 1 - 3 i}{2}; a \neq = 0

簡素化

3 - \frac{c}{ab} : - 3 \frac{c}{ab}

簡素化

3 - \frac{c}{ab} \frac{- 1 + 3 i}{2} : - \frac{3 c ( - 1 + 3 i )}{2 3 ab}

簡素化

3 - \frac{c}{ab} \frac{- 1 - 3 i}{2} : - \frac{3 c ( - 1 - 3 i )}{2 3 ab}

x = - 3 \frac{c}{ab}, x = - \frac{3 c ( - 1 + 3 i )}{2 3 ab}, x = - \frac{3 c ( - 1 - 3 i )}{2 3 ab}; a \neq = 0

グラフ

人気の例

(x - 4)^{3} = 729

7x^3-3x^2-35x+15=0

7 x^{3} - 3 x^{2} - 35 x + 15 = 0

1-y^2=y^4-y^2+y-1

1 - y^{2} = y^{4} - y^{2} + y - 1

4 x^{12} = 6

(x-9)(x^2-36)=0

(x - 9) (x^{2} - 36) = 0