y^3=5

Lösung

y^{3} = 5

y = 35, y = - 35 \frac{1}{2} + 35 \frac{3}{2} i, y = - 35 \frac{1}{2} - 35 \frac{3}{2} i

Schritte zur Lösung

y^{3} = 5

Für

x^{3} = f (a)

sind die Lösungen

x = 3 f (a), 3 f (a) \frac{- 1 - 3 i}{2}, 3 f (a) \frac{- 1 + 3 i}{2}

y = 35, y = 35 \frac{- 1 + 3 i}{2}, y = 35 \frac{- 1 - 3 i}{2}

Vereinfache

35 \frac{- 1 + 3 i}{2} : - 35 \frac{1}{2} + 35 \frac{3}{2} i

Vereinfache

35 \frac{- 1 - 3 i}{2} : - 35 \frac{1}{2} - 35 \frac{3}{2} i

y = 35, y = - 35 \frac{1}{2} + 35 \frac{3}{2} i, y = - 35 \frac{1}{2} - 35 \frac{3}{2} i

x^{4} - 18 x^{2} - x + 78 = 0

x^{3} - 4 x^{2} - 9 x + 12 = 0

x^{3} + 5 x^{2} - 16 x - 80 = 0

6 x^{8} + 6 = 13 x^{4}

x^{3} - 7 x + 4 = 0