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Beliebt Algebra >

(x-3)(x+1)^2(x^2-4x+13)=0

Lösung

(x - 3) (x + 1)^{2} (x^{2} - 4 x + 13) = 0

Lösung

x = 3, x = - 1, x = 2 + 3 i, x = 2 - 3 i

Schritte zur Lösung

(x - 3) (x + 1)^{2} (x^{2} - 4 x + 13) = 0

Anwendung des Nullfaktorprinzips: Wenn

ab = 0

dann

a = 0

oder

b = 0

x - 3 = 0 or x + 1 = 0 or x^{2} - 4 x + 13 = 0

Löse

x - 3 = 0 : x = 3

Löse

x + 1 = 0 : x = - 1

Löse

x^{2} - 4 x + 13 = 0 : x = 2 + 3 i, x = 2 - 3 i

Die Lösungen sind

x = 3, x = - 1, x = 2 + 3 i, x = 2 - 3 i

Graph

Beliebte Beispiele

4 y^{3} - 2 y + 5 = 0

6x^4-81x^2+162=0

6 x^{4} - 81 x^{2} + 162 = 0

solvefor x,f=x^3h

so l v e f or x, f = x^{3} h

x^3-8x^2-4x+32=0

x^{3} - 8 x^{2} - 4 x + 32 = 0

x^{4} = 3 x^{2}