d^3=125

Lösung

d^{3} = 125

d = 5, d = - \frac{5}{2} + \frac{5 3}{2} i, d = - \frac{5}{2} - \frac{5 3}{2} i

Schritte zur Lösung

d^{3} = 125

Für

x^{3} = f (a)

sind die Lösungen

x = 3 f (a), 3 f (a) \frac{- 1 - 3 i}{2}, 3 f (a) \frac{- 1 + 3 i}{2}

d = 3125, d = 3125 \frac{- 1 + 3 i}{2}, d = 3125 \frac{- 1 - 3 i}{2}

3125 = 5

Vereinfache

3125 \frac{- 1 + 3 i}{2} : - \frac{5}{2} + \frac{5 3}{2} i

Vereinfache

3125 \frac{- 1 - 3 i}{2} : - \frac{5}{2} - \frac{5 3}{2} i

d = 5, d = - \frac{5}{2} + \frac{5 3}{2} i, d = - \frac{5}{2} - \frac{5 3}{2} i

(x) = x^{3} + 2 x^{2} - 5 x - 6

so l v e f or R, 1 R = R^{1} + R^{2} R^{1} X R^{2}

t^{4} = 1

so l v e f or z, z^{5} = - 32

x^{3} - 2 x^{2} - x + 1 = x^{2} - 3 x + 1