d^3=125

解

d^{3} = 125

d = 5, d = - \frac{5}{2} + \frac{5 3}{2} i, d = - \frac{5}{2} - \frac{5 3}{2} i

解答ステップ

d^{3} = 125

x^{3} = f (a)

では, 解は

x = 3 f (a), 3 f (a) \frac{- 1 - 3 i}{2}, 3 f (a) \frac{- 1 + 3 i}{2}

d = 3125, d = 3125 \frac{- 1 + 3 i}{2}, d = 3125 \frac{- 1 - 3 i}{2}

3125 = 5

簡素化

3125 \frac{- 1 + 3 i}{2} : - \frac{5}{2} + \frac{5 3}{2} i

簡素化

3125 \frac{- 1 - 3 i}{2} : - \frac{5}{2} - \frac{5 3}{2} i

d = 5, d = - \frac{5}{2} + \frac{5 3}{2} i, d = - \frac{5}{2} - \frac{5 3}{2} i