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人気のある代数 >

solvefor y,x=ysqrt(1-y^2)

解

解く

y, x = y 1 - y^{2}

解

y = - \frac{- 1 + 1 - 4 x ^{2}}{2} {0 \leq v < \frac{1}{2} or x = \frac{1}{2}}, y = - - \frac{- 1 + 1 - 4 x ^{2}}{2} {- \frac{1}{2} \leq v < 0 or x = 0}, y = - \frac{- 1 - 1 - 4 x ^{2}}{2} {0 \leq v < \frac{1}{2} or x = \frac{1}{2}}, y = - - \frac{- 1 - 1 - 4 x ^{2}}{2} {- \frac{1}{2} \leq v < 0 or x = 0}

解答ステップ

x = y 1 - y^{2}

両辺を2乗する:

x^{2} = y^{2} - y^{4}

x^{2} = y^{2} - y^{4}

解く

x^{2} = y^{2} - y^{4} : y = - \frac{- 1 + 1 - 4 x ^{2}}{2}, y = - - \frac{- 1 + 1 - 4 x ^{2}}{2}, y = - \frac{- 1 - 1 - 4 x ^{2}}{2}, y = - - \frac{- 1 - 1 - 4 x ^{2}}{2}

y = - \frac{- 1 + 1 - 4 x ^{2}}{2}, y = - - \frac{- 1 + 1 - 4 x ^{2}}{2}, y = - \frac{- 1 - 1 - 4 x ^{2}}{2}, y = - - \frac{- 1 - 1 - 4 x ^{2}}{2}

解を検算する:

y = - \frac{- 1 + 1 - 4 x ^{2}}{2} {0 \leq v < \frac{1}{2} or x = \frac{1}{2}}, y = - - \frac{- 1 + 1 - 4 x ^{2}}{2} {- \frac{1}{2} \leq v < 0 or x = 0}, y = - \frac{- 1 - 1 - 4 x ^{2}}{2} {0 \leq v < \frac{1}{2} or x = \frac{1}{2}}, y = - - \frac{- 1 - 1 - 4 x ^{2}}{2} {- \frac{1}{2} \leq v < 0 or x = 0}

解答は

y = - \frac{- 1 + 1 - 4 x ^{2}}{2} {0 \leq v < \frac{1}{2} or x = \frac{1}{2}}, y = - - \frac{- 1 + 1 - 4 x ^{2}}{2} {- \frac{1}{2} \leq v < 0 or x = 0}, y = - \frac{- 1 - 1 - 4 x ^{2}}{2} {0 \leq v < \frac{1}{2} or x = \frac{1}{2}}, y = - - \frac{- 1 - 1 - 4 x ^{2}}{2} {- \frac{1}{2} \leq v < 0 or x = 0}

グラフ

人気の例

1-1/(sqrt(x))=0

1 - \frac{1}{x} = 0

2 x + 4 = 0

4x-11x^{1/2}+6=0

4 x - 11 x^{\frac{1}{2}} + 6 = 0

sqrt(z)sqrt(z-7)=12

z z - 7 = 12

(sqrt(y)-1)^2=5-sqrt(y)

(y - 1)^{2} = 5 - y