solvefor x,sqrt((x^2+a))=2x

解

x, (x^{2} + a) = 2 x

x = \frac{a}{3} {a \geq 0}, x = - \frac{a}{3} {a = 0}

解答ステップ

(x^{2} + a) = 2 x

両辺を2乗する:

x^{2} + a = 4 x^{2}

x^{2} + a = 4 x^{2}

解く

x^{2} + a = 4 x^{2} : x = \frac{a}{3}, x = - \frac{a}{3}

x = \frac{a}{3}, x = - \frac{a}{3}

解を検算する:

x = \frac{a}{3} {a \geq 0}, x = - \frac{a}{3} {a = 0}

解答は

x = \frac{a}{3} {a \geq 0}, x = - \frac{a}{3} {a = 0}